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Math help (basic to advanced)

dmention7

dmention7

Hater
First rearrange the equations:

y=-x+8
y=x+4

Then plot them by calculating a pair of points from each equation, e.g.

(0,8) (2,6)
(0,4) (2,6)

(whoops I solved it for you... lol)
 
Workdawg

Workdawg

NARWHAL
To assist with that... the y intercept is the point on the graph where X = 0... so once you've solved for Y, plug in 0 for X and see what Y is.
 
dmention7

dmention7

Hater
First equation....

subtract x from both sides

x + y -x = 8 -x

now the x's on the left cancel out

y = 8 - x


Second equation.....

again, subtract x from both sides

x - y - x = -4 - x

the x's on the left cancel out

-y = -4 - x

to make the y positive, multiply both sides by -1

-y(-1) = -4(-1) - x(-1)

all multiplying by -1 does is change all the signs

y = 4 + x
 
Z

Z-licious

Guest
Speed6 Guy said:
Ok guys sorry for this but I need help fast.

Factor these completely.



and

100y^22 - 81z^20
Click to expand...
3p^4 - 48q^4

This is the difference between two squares:

a^2 - b^2

a^2 - b^2 = (a+b)(a-b)

So, we take your equation: 3p^4 - 48q^4

a^2 = 3p^4 and b^2 = 48q^4

so you'll have to take the square root of each to find a and b. I will refer to the square root of a value as rt(x) from now on. I.E. rt(25)=5

a = rt(3) * p^2 and b = rt(48) * q^2

Now that we have a and b, you plug them back into the expression (a+b)(a-b) to get

(rt(3)p^2 + rt(48)q^2)(rt(3)p^2 - rt(48)q^2)

Now if you want to check your work, FOIL it out and make sure it matches the original expresson.







For the 2nd one, we do the same steps

100y^22 - 81z^20

a^2 = 100y^22 and b^2=81z^20

so

a = 10y^11 and b = 9z^10
 
Bartron8000

Bartron8000

New Member
IDK if anyone has mentioned this yet but there is a website called Cramster, they solve problems out of text books for a ton of classes and walk you through how to solve them. This was a wonder for me in physics. Only down side is that you can only get half of the problems for free, otherwise you have to pay to get all the problems. Oh and I forgot that you can post questions about problems and usually someone can help you out there too.
 
dmention7

dmention7

Hater
(c^2-4c-3)-(c4^2+3c+7)

distribute the - sign through the second term:

c^2 - 4c - 3 -4c^2 - 3c - 7

then, just combine the terms that have the same power of c:

-3c^2 - 7c - 10
 
dmention7

dmention7

Hater
That's correct. I'm not familiar with how that site takes its answers, but double check any parentheses you are using. Maybe the fact that you're using a capital lambda is what's messing it up?
 
Z

Z-licious

Guest
To solve for A you need to get just A on one side of the = sign and everything else on the other side. Mofo did it properly.
 
Big Nate

Big Nate

Chaos Engineer
The web site was hacked i think. Cause it now tells me that the site may down for up to four hours tonight due to issues.
 
Big Nate

Big Nate

Chaos Engineer
Solve the equation, if possible. (If the equation is an identity or a contradiction, so indicate by entering IDENTITY or CONTRADICTION.)

 
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